Divisibility tests
Last updated: 9 Jul 2008
Remember you will not have a calculator in the GMAT.
So when you are looking for factors of a number, either because that is explicitly asked of you in a question or you are simplifying a fraction then the following tests will be useful.
Divisible by 2
Every number which ends with 0, 2, 4, 6 or 8 is divisible by 2, and is therefore an even number.
For example:
- 258 ends in the number '8' and therefore is divisible by 2.
- 1783 ends in the number '3' and is therefor not divisible by 2
Divisible by 3
If the sum of the digits in a number is divisible by 3 then the number is divisible by 3.
For example:
- The sum of the digits in 105 is 6 which is divisible by 3 so 105 is divisible by 3.
- The sum of the digits in 236 is 11 which is not divisible by 3 so 236 is not divisible by 3.
Divisible by 4
If the last 2 digits of the number are divisible by 4 then the whole number is divisible by 4.
For example
- The last two digits of 932 are '32' which is divisible by 4 so 932 is divisible by 4.
- The last two digits of 1014 are '14' which is not divisible by 4 so 1014 is not divisible by 4.
Divisible by 5
If the last digit of a number is 0 or 5 then the number is divisible by 5.
For example:
- The last digit of 1025 is '5' therefore 1025 is divisible by 5.
- The last digit of 324 is '4' therefore 324 is not divisible by 5.
Tip: Dividing by 5 is the same as multiplying by 2 and then dividing by 10. However multiplying by 2 and then dividing by 10 is much easier for most people to do without a calculator.
For example what is 235 divided by 5?
235 x 2 is 470. 470 divided by 10 is 47.
Therefore 235 divided by 5 is 47.
Divisible by 6
To be divisible by 6 a number must be divisible by 2 and by 3, so if it passes both these earlier tests then it is divisible by 6. I.e. the last digit is 0, 2, 4, 6 or 8 and the sum of the digits is divisible by 3.
Divisible by 7
I am afraid that about the easiest way to check for divisibility by 7 is to do the long division.
Divisible by 8
If the last 3 digits of the number are divisible by 8 then the whole number is divisible by 8.
If the sum of the digits is divisible by 9 then the number is divisible by 9. For example:
Divisible by 9
Numbers Divisible by 7
To determine if a number is divisible by 7, take the last digit off the number, double it and subtract the doubled number from the remaining number. If the result is evenly divisible by 7 (e.g. 14, 7, 0, -7, etc.), then the number is divisible by seven. This may need to be repeated several times.
Example: Is 3101 evenly divisible by 7?
310 - take off the last digit of the number which was 1
-2 - double the removed digit and subtract it
308 - repeat the process by taking off the 8
-16 - and doubling it to get 16 which is subtracted
14 - the result is 14 which is a multiple of 7
Thanks for suggessting this I had not seen it before. I am not sure how much easier it is than actually doing the division but I am sure there ill be those who find it very useful.