Combinations
Last updated: 20 Mar 2009
Unlike a permutation, in a combination the order of the objects selected does not matter. For example, if you were choosing a team of three students from a class of ten, the order you said "Joe, Sally, John" would not matter to who is in the group- saying "Sally, Joe, John" instead doesn't change anything.
How to solve a combination
The number of ways you can make a combination of r objects out of a set of n objects is made from the formula below:
An explanation
You may be asking (like I did when I learned this material), "What? That formula doesn't make sense!". However, it is based on the formula for a permutation.
If you think about it, the makes perfect sense - that is how many options you'd have if you picked in order from all of them.
Removing the gets it down to just the numbers you want, where
equals the last number you aren't picking. If you pick 3 from 5, it'll be
Which accomplishes the "pick x of 5" part.
The extra removes all the redundant options. For example, say you have 6 different balls, labelled A through F. If you pick three, you can pick ABC, ABD, ABE, ABF, etc. You'll end up with six of the same — ABC, ACB, BAC, BCA, CAB, CBA — all of which only count as one in a combination. As you'll notice, since we picked 3,
- the same number we have to divide out!
An example of a combination
Lets take the example above. Out of a class of ten students, how many ways could you make a team of three students? We know is ten because the set (the students) has ten objects in it. We know
is 3 because the team will have three students on it. To solve, we use the combinations equation.
By taking apart the factorials, we can simplify the 10! and 7!. Alternatively, just start at 10 and multiply down, stopping right before 7.
There you have it, there are 120 ways to pick a team of 3 people out of ten.
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