Summary of rate problems

Last updated: 20 May 2008

Standard rate formulas

Rate = `text{Amount} / text{Time}`

Time = `text{Amount} / text{Time}`

Amount = Rate x Time

Where rate could be widgets per second or gallons per hour or houses per day etc.

Speed, distance and time

When it comes to travel the formulas are the same it's jsut the terms which change

Average speed = `text{Distance} / text{Time}`

Time = `text{Distance} / text{Average Speed}`

Distance = Average Speed x Time

Combined work rate formula

`1/T_{a} + 1/T_{b} + 1/T_{c} + ... = 1/T_{text{together}}`

Where `T_{a}`, `T_{b}`, `T_{c}`,... are the times taken by a, b, c... respectively to complete the task alone and `T_{text{together}}` is the time taken by them to complete the task when they are all working together.

Further reading

Next page: Practice Questions

Comments (2):

  1. Hello, can somebody solve this question and post it here please?
    A leopard is 200 meters away from a deer. The leopard wants to catch the deer and its speed is 12km/h whereas deer's is 10km/h. If they start running at the same time, how many kilometers will the deer have run when it is caught?
    Thanks.

    Anonymous on 21 Feb 2007 (permalink)
  2. This speed-distance-time question is very similar and is explained here.

    If this doesn't help then say and I'll post an explanation to the question above.

    joel on 23 Feb 2007 (permalink)

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